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How do you calculate the air required for combustion?

  1. Theoretical oxygen demand from elemental analysis (mass basis)
    Let elemental mass fractions (kg/kg fuel) be C,H,O,SC,H,O,S, theoretical oxygen demand:
  • O2,0=2.667C+8H+1SOO_{2,0} = 2.667C + 8H + 1S - O (kg O2O_2/kg fuel)

Oxygen mass fraction in air is about 0.2320.232, theoretical air demand (mass):

  • L0=O2,00.232L_0 = \dfrac{O_{2,0}}{0.232} (kg air/kg fuel)

Actual air:

  • L=αL0L = \alpha L_0
  1. Volumetric method (standard state)
    First compute theoretical oxygen demand (kmol/kg fuel):
  • nO2,0=C12+H4+S32O32n_{O_2,0} = \dfrac{C}{12} + \dfrac{H}{4} + \dfrac{S}{32} - \dfrac{O}{32}

Theoretical air (kmol):

  • nair,0=nO2,00.21n_{air,0} = \dfrac{n_{O_2,0}}{0.21}

Standard-state volume:

  • Vair,0=22.414 nair,0V_{air,0} = 22.414\ n_{air,0} (m^3/kg, 0C0^\circ C, 101.325 kPa)